Metamath Proof Explorer


Theorem equsalvw

Description: Version of equsalv with a disjoint variable condition, and of equsal with two disjoint variable conditions, which requires fewer axioms. See also the dual form equsexvw . (Contributed by BJ, 31-May-2019)

Ref Expression
Hypothesis equsalvw.1 ⊢ x = y → φ ↔ ψ
Assertion equsalvw ⊢ ∀ x x = y → φ ↔ ψ

Proof

Step Hyp Ref Expression
1 equsalvw.1 ⊢ x = y → φ ↔ ψ
2 1 pm5.74i ⊢ x = y → φ ↔ x = y → ψ
3 2 albii ⊢ ∀ x x = y → φ ↔ ∀ x x = y → ψ
4 equsv ⊢ ∀ x x = y → ψ ↔ ψ
5 3 4 bitri ⊢ ∀ x x = y → φ ↔ ψ