Metamath Proof Explorer


Theorem equsb3

Description: Substitution in an equality. (Contributed by Raph Levien and FL, 4-Dec-2005) Reduce axiom usage. (Revised by Wolf Lammen, 23-Jul-2023)

Ref Expression
Assertion equsb3 ⊢ y x x = z ↔ y = z

Proof

Step Hyp Ref Expression
1 equequ1 ⊢ x = w → x = z ↔ w = z
2 equequ1 ⊢ w = y → w = z ↔ y = z
3 1 2 sbievw2 ⊢ y x x = z ↔ y = z