Metamath Proof Explorer


Theorem eqvreleqd

Description: Equality theorem for equivalence relation, deduction version. (Contributed by Peter Mazsa, 23-Sep-2021)

Ref Expression
Hypothesis eqvreleqd.1 ⊢ φ → R = S
Assertion eqvreleqd ⊢ φ → EqvRel R ↔ EqvRel S

Proof

Step Hyp Ref Expression
1 eqvreleqd.1 ⊢ φ → R = S
2 eqvreleq ⊢ R = S → EqvRel R ↔ EqvRel S
3 1 2 syl ⊢ φ → EqvRel R ↔ EqvRel S