Metamath Proof Explorer


Theorem eupthcl

Description: An Eulerian path has length # ( F ) , which is an integer. (Contributed by Mario Carneiro, 12-Mar-2015) (Revised by AV, 18-Feb-2021)

Ref Expression
Assertion eupthcl ⊢ F EulerPaths ⁡ G P → F ∈ ℕ 0

Proof

Step Hyp Ref Expression
1 eqid ⊢ iEdg ⁡ G = iEdg ⁡ G
2 1 eupthi ⊢ F EulerPaths ⁡ G P → F Walks ⁡ G P ∧ F : 0 ..^ F ⟶ 1-1 onto dom ⁡ iEdg ⁡ G
3 wlkcl ⊢ F Walks ⁡ G P → F ∈ ℕ 0
4 3 adantr ⊢ F Walks ⁡ G P ∧ F : 0 ..^ F ⟶ 1-1 onto dom ⁡ iEdg ⁡ G → F ∈ ℕ 0
5 2 4 syl ⊢ F EulerPaths ⁡ G P → F ∈ ℕ 0