Metamath Proof Explorer


Theorem exexneq

Description: There exist two different sets. (Contributed by NM, 7-Nov-2006) Avoid ax-13 . (Revised by BJ, 31-May-2019) Avoid ax-8 . (Revised by SN, 21-Sep-2023) Avoid ax-12 . (Revised by Rohan Ridenour, 9-Oct-2024) Use ax-pr instead of ax-pow . (Revised by BTernaryTau, 3-Dec-2024) Extract this result from the proof of dtru . (Revised by BJ, 2-Jan-2025)

Ref Expression
Assertion exexneq ⊢ ∃ x ∃ y ¬ x = y

Proof

Step Hyp Ref Expression
1 exel ⊢ ∃ x ∃ z z ∈ x
2 ax-nul ⊢ ∃ y ∀ z ¬ z ∈ y
3 exdistrv ⊢ ∃ x ∃ y ∃ z z ∈ x ∧ ∀ z ¬ z ∈ y ↔ ∃ x ∃ z z ∈ x ∧ ∃ y ∀ z ¬ z ∈ y
4 1 2 3 mpbir2an ⊢ ∃ x ∃ y ∃ z z ∈ x ∧ ∀ z ¬ z ∈ y
5 ax9v1 ⊢ x = y → z ∈ x → z ∈ y
6 5 eximdv ⊢ x = y → ∃ z z ∈ x → ∃ z z ∈ y
7 df-ex ⊢ ∃ z z ∈ y ↔ ¬ ∀ z ¬ z ∈ y
8 6 7 imbitrdi ⊢ x = y → ∃ z z ∈ x → ¬ ∀ z ¬ z ∈ y
9 8 com12 ⊢ ∃ z z ∈ x → x = y → ¬ ∀ z ¬ z ∈ y
10 9 con2d ⊢ ∃ z z ∈ x → ∀ z ¬ z ∈ y → ¬ x = y
11 10 imp ⊢ ∃ z z ∈ x ∧ ∀ z ¬ z ∈ y → ¬ x = y
12 11 2eximi ⊢ ∃ x ∃ y ∃ z z ∈ x ∧ ∀ z ¬ z ∈ y → ∃ x ∃ y ¬ x = y
13 4 12 ax-mp ⊢ ∃ x ∃ y ¬ x = y