Metamath Proof Explorer


Theorem exp5k

Description: An exportation inference. (Contributed by Jeff Hankins, 7-Jul-2009)

Ref Expression
Hypothesis exp5k.1 ⊢ φ → ψ ∧ χ ∧ θ ∧ τ → η
Assertion exp5k ⊢ φ → ψ → χ → θ → τ → η

Proof

Step Hyp Ref Expression
1 exp5k.1 ⊢ φ → ψ ∧ χ ∧ θ ∧ τ → η
2 1 expd ⊢ φ → ψ ∧ χ ∧ θ → τ → η
3 2 exp4d ⊢ φ → ψ → χ → θ → τ → η