Metamath Proof Explorer


Theorem exp5k

Description: An exportation inference. (Contributed by Jeff Hankins, 7-Jul-2009)

Ref Expression
Hypothesis exp5k.1 ⊢ ( 𝜑 → ( ( ( 𝜓 ∧ ( 𝜒 ∧ 𝜃 ) ) ∧ 𝜏 ) → 𝜂 ) )
Assertion exp5k ( 𝜑 → ( 𝜓 → ( 𝜒 → ( 𝜃 → ( 𝜏 → 𝜂 ) ) ) ) )

Proof

Step Hyp Ref Expression
1 exp5k.1 ⊢ ( 𝜑 → ( ( ( 𝜓 ∧ ( 𝜒 ∧ 𝜃 ) ) ∧ 𝜏 ) → 𝜂 ) )
2 1 expd ⊢ ( 𝜑 → ( ( 𝜓 ∧ ( 𝜒 ∧ 𝜃 ) ) → ( 𝜏 → 𝜂 ) ) )
3 2 exp4d ⊢ ( 𝜑 → ( 𝜓 → ( 𝜒 → ( 𝜃 → ( 𝜏 → 𝜂 ) ) ) ) )