Metamath Proof Explorer


Theorem expd

Description: Exportation deduction. (Contributed by NM, 20-Aug-1993) (Proof shortened by Wolf Lammen, 28-Jul-2022)

Ref Expression
Hypothesis expd.1 ⊢ φ → ψ ∧ χ → θ
Assertion expd ⊢ φ → ψ → χ → θ

Proof

Step Hyp Ref Expression
1 expd.1 ⊢ φ → ψ ∧ χ → θ
2 1 expdcom ⊢ ψ → χ → φ → θ
3 2 com3r ⊢ φ → ψ → χ → θ