Metamath Proof Explorer


Theorem expcomd

Description: Deduction form of expcom . (Contributed by Alan Sare, 22-Jul-2012)

Ref Expression
Hypothesis expcomd.1 φ ψ χ θ
Assertion expcomd φ χ ψ θ

Proof

Step Hyp Ref Expression
1 expcomd.1 φ ψ χ θ
2 1 expd φ ψ χ θ
3 2 com23 φ χ ψ θ