Theorem expcomd

Description: Deduction form of expcom . (Contributed by Alan Sare, 22-Jul-2012)

	Ref	Expression
Hypothesis	expcomd.1	⊢ ( 𝜑 → ( ( 𝜓 ∧ 𝜒 ) → 𝜃 ) )
Assertion	expcomd	⊢ ( 𝜑 → ( 𝜒 → ( 𝜓 → 𝜃 ) ) )

Proof

Step	Hyp	Ref	Expression
1		expcomd.1	⊢ ( 𝜑 → ( ( 𝜓 ∧ 𝜒 ) → 𝜃 ) )
2	1	expd	⊢ ( 𝜑 → ( 𝜓 → ( 𝜒 → 𝜃 ) ) )
3	2	com23	⊢ ( 𝜑 → ( 𝜒 → ( 𝜓 → 𝜃 ) ) )