Metamath Proof Explorer


Theorem ffun

Description: A mapping is a function. (Contributed by NM, 3-Aug-1994) (Proof shortened by Umit Teoman Dogan, 10-Jun-2026)

Ref Expression
Assertion ffun ⊢ F : A ⟶ B → Fun ⁡ F

Proof

Step Hyp Ref Expression
1 ffn ⊢ F : A ⟶ B → F Fn A
2 1 fnfund ⊢ F : A ⟶ B → Fun ⁡ F