Metamath Proof Explorer


Theorem flimneiss

Description: A filter contains the neighborhood filter as a subfilter. (Contributed by Mario Carneiro, 9-Apr-2015) (Revised by Stefan O'Rear, 9-Aug-2015)

Ref Expression
Assertion flimneiss ⊢ A ∈ J fLim F → nei ⁡ J ⁡ A ⊆ F

Proof

Step Hyp Ref Expression
1 eqid ⊢ ⋃ J = ⋃ J
2 1 elflim2 ⊢ A ∈ J fLim F ↔ J ∈ Top ∧ F ∈ ⋃ ran ⁡ Fil ∧ F ⊆ 𝒫 ⋃ J ∧ A ∈ ⋃ J ∧ nei ⁡ J ⁡ A ⊆ F
3 2 simprbi ⊢ A ∈ J fLim F → A ∈ ⋃ J ∧ nei ⁡ J ⁡ A ⊆ F
4 3 simprd ⊢ A ∈ J fLim F → nei ⁡ J ⁡ A ⊆ F