Metamath Proof Explorer


Theorem fmtno1

Description: The 1 st Fermat number, see remark in ApostolNT p. 7. (Contributed by AV, 13-Jun-2021)

Ref Expression
Assertion fmtno1 ⊢ FermatNo ⁡ 1 = 5

Proof

Step Hyp Ref Expression
1 1nn0 ⊢ 1 ∈ ℕ 0
2 fmtno ⊢ 1 ∈ ℕ 0 → FermatNo ⁡ 1 = 2 2 1 + 1
3 1 2 ax-mp ⊢ FermatNo ⁡ 1 = 2 2 1 + 1
4 2cn ⊢ 2 ∈ ℂ
5 exp1 ⊢ 2 ∈ ℂ → 2 1 = 2
6 4 5 ax-mp ⊢ 2 1 = 2
7 6 oveq2i ⊢ 2 2 1 = 2 2
8 7 oveq1i ⊢ 2 2 1 + 1 = 2 2 + 1
9 sq2 ⊢ 2 2 = 4
10 9 oveq1i ⊢ 2 2 + 1 = 4 + 1
11 4p1e5 ⊢ 4 + 1 = 5
12 8 10 11 3eqtri ⊢ 2 2 1 + 1 = 5
13 3 12 eqtri ⊢ FermatNo ⁡ 1 = 5