Metamath Proof Explorer


Theorem fmtno3

Description: The 3 rd Fermat number, see remark in ApostolNT p. 7. (Contributed by AV, 13-Jun-2021)

Ref Expression
Assertion fmtno3 ⊢ FermatNo ⁡ 3 = 257

Proof

Step Hyp Ref Expression
1 3nn0 ⊢ 3 ∈ ℕ 0
2 fmtno ⊢ 3 ∈ ℕ 0 → FermatNo ⁡ 3 = 2 2 3 + 1
3 1 2 ax-mp ⊢ FermatNo ⁡ 3 = 2 2 3 + 1
4 cu2 ⊢ 2 3 = 8
5 4 oveq2i ⊢ 2 2 3 = 2 8
6 5 oveq1i ⊢ 2 2 3 + 1 = 2 8 + 1
7 2exp8 ⊢ 2 8 = 256
8 7 oveq1i ⊢ 2 8 + 1 = 256 + 1
9 2nn0 ⊢ 2 ∈ ℕ 0
10 5nn0 ⊢ 5 ∈ ℕ 0
11 9 10 deccl ⊢ 25 ∈ ℕ 0
12 6nn0 ⊢ 6 ∈ ℕ 0
13 6p1e7 ⊢ 6 + 1 = 7
14 eqid ⊢ 256 = 256
15 11 12 13 14 decsuc ⊢ 256 + 1 = 257
16 6 8 15 3eqtri ⊢ 2 2 3 + 1 = 257
17 3 16 eqtri ⊢ FermatNo ⁡ 3 = 257