Metamath Proof Explorer


Theorem fnbrfvb2

Description: Version of fnbrfvb for functions on Cartesian products: function value expressed as a binary relation. See fnbrovb for the form when F is seen as a binary operation. (Contributed by BJ, 15-Feb-2022)

Ref Expression
Assertion fnbrfvb2 ⊢ F Fn V × W ∧ A ∈ V ∧ B ∈ W → F ⁡ A B = C ↔ A B F C

Proof

Step Hyp Ref Expression
1 opelxpi ⊢ A ∈ V ∧ B ∈ W → A B ∈ V × W
2 fnbrfvb ⊢ F Fn V × W ∧ A B ∈ V × W → F ⁡ A B = C ↔ A B F C
3 1 2 sylan2 ⊢ F Fn V × W ∧ A ∈ V ∧ B ∈ W → F ⁡ A B = C ↔ A B F C