Metamath Proof Explorer


Theorem fnund

Description: The union of two functions with disjoint domains, a deduction version. (Contributed by metakunt, 28-May-2024)

Ref Expression
Hypotheses fnund.1 φFFnA
fnund.2 φGFnB
fnund.3 φAB=
Assertion fnund φFGFnAB

Proof

Step Hyp Ref Expression
1 fnund.1 φFFnA
2 fnund.2 φGFnB
3 fnund.3 φAB=
4 fnun FFnAGFnBAB=FGFnAB
5 1 2 3 4 syl21anc φFGFnAB