Metamath Proof Explorer


Theorem frgpgrp

Description: The free group is a group. (Contributed by Mario Carneiro, 1-Oct-2015)

Ref Expression
Hypothesis frgpgrp.g G = freeGrp I
Assertion frgpgrp I V G Grp

Proof

Step Hyp Ref Expression
1 frgpgrp.g G = freeGrp I
2 eqid ~ FG I = ~ FG I
3 1 2 frgp0 I V G Grp ~ FG I = 0 G
4 3 simpld I V G Grp