Metamath Proof Explorer


Theorem grpsubcl

Description: Closure of group subtraction. (Contributed by NM, 31-Mar-2014)

Ref Expression
Hypotheses grpsubcl.b ⊢ B = Base G
grpsubcl.m ⊢ - ˙ = - G
Assertion grpsubcl ⊢ G ∈ Grp ∧ X ∈ B ∧ Y ∈ B → X - ˙ Y ∈ B

Proof

Step Hyp Ref Expression
1 grpsubcl.b ⊢ B = Base G
2 grpsubcl.m ⊢ - ˙ = - G
3 1 2 grpsubf ⊢ G ∈ Grp → - ˙ : B × B ⟶ B
4 fovcdm ⊢ - ˙ : B × B ⟶ B ∧ X ∈ B ∧ Y ∈ B → X - ˙ Y ∈ B
5 3 4 syl3an1 ⊢ G ∈ Grp ∧ X ∈ B ∧ Y ∈ B → X - ˙ Y ∈ B