Metamath Proof Explorer


Theorem gsumsnd

Description: Group sum of a singleton, deduction form. (Contributed by Thierry Arnoux, 30-Jan-2017) (Proof shortened by AV, 11-Dec-2019)

Ref Expression
Hypotheses gsumsnd.b ⊢ B = Base G
gsumsnd.g ⊢ φ → G ∈ Mnd
gsumsnd.m ⊢ φ → M ∈ V
gsumsnd.c ⊢ φ → C ∈ B
gsumsnd.s ⊢ φ ∧ k = M → A = C
Assertion gsumsnd ⊢ φ → ∑ G k ∈ M A = C

Proof

Step Hyp Ref Expression
1 gsumsnd.b ⊢ B = Base G
2 gsumsnd.g ⊢ φ → G ∈ Mnd
3 gsumsnd.m ⊢ φ → M ∈ V
4 gsumsnd.c ⊢ φ → C ∈ B
5 gsumsnd.s ⊢ φ ∧ k = M → A = C
6 nfv ⊢ Ⅎ k φ
7 nfcv ⊢ Ⅎ _ k C
8 1 2 3 4 5 6 7 gsumsnfd ⊢ φ → ∑ G k ∈ M A = C