Metamath Proof Explorer


Theorem hlne2

Description: The half-line relation implies inequality. (Contributed by Thierry Arnoux, 22-Feb-2020)

Ref Expression
Hypotheses ishlg.p ⊢ P = Base G
ishlg.i ⊢ I = Itv ⁡ G
ishlg.k ⊢ K = hl 𝒢 ⁡ G
ishlg.a ⊢ φ → A ∈ P
ishlg.b ⊢ φ → B ∈ P
ishlg.c ⊢ φ → C ∈ P
ishlg.g ⊢ φ → G ∈ V
hlcomd.1 ⊢ φ → A K ⁡ C B
Assertion hlne2 ⊢ φ → B ≠ C

Proof

Step Hyp Ref Expression
1 ishlg.p ⊢ P = Base G
2 ishlg.i ⊢ I = Itv ⁡ G
3 ishlg.k ⊢ K = hl 𝒢 ⁡ G
4 ishlg.a ⊢ φ → A ∈ P
5 ishlg.b ⊢ φ → B ∈ P
6 ishlg.c ⊢ φ → C ∈ P
7 ishlg.g ⊢ φ → G ∈ V
8 hlcomd.1 ⊢ φ → A K ⁡ C B
9 1 2 3 4 5 6 7 ishlg ⊢ φ → A K ⁡ C B ↔ A ≠ C ∧ B ≠ C ∧ A ∈ C I B ∨ B ∈ C I A
10 8 9 mpbid ⊢ φ → A ≠ C ∧ B ≠ C ∧ A ∈ C I B ∨ B ∈ C I A
11 10 simp2d ⊢ φ → B ≠ C