Metamath Proof Explorer


Theorem hpgssplng

Description: Any point X on a half plane defined by a line A and another point Y is on the plane defined by A and Y . (Contributed by Thierry Arnoux, 5-Jul-2026)

Ref Expression
Hypotheses hpgssplng.p P = Base G
hpgssplng.l L = Line 𝒢 G
hpgssplng.e No typesetting found for |- E = ( PlnG ` G ) with typecode |-
hpgssplng.a φ A ran L
hpgssplng.x φ X P
hpgssplng.y φ Y P A
hpgssplng.g φ G 𝒢 Tarski
hpgssplng.1 φ X hp 𝒢 G A Y
Assertion hpgssplng φ X A E Y

Proof

Step Hyp Ref Expression
1 hpgssplng.p P = Base G
2 hpgssplng.l L = Line 𝒢 G
3 hpgssplng.e Could not format E = ( PlnG ` G ) : No typesetting found for |- E = ( PlnG ` G ) with typecode |-
4 hpgssplng.a φ A ran L
5 hpgssplng.x φ X P
6 hpgssplng.y φ Y P A
7 hpgssplng.g φ G 𝒢 Tarski
8 hpgssplng.1 φ X hp 𝒢 G A Y
9 8 3mix2d φ X A X hp 𝒢 G A Y X a b | a P A b P A t A t a Itv G b Y
10 eqid Itv G = Itv G
11 eqid a b | a P A b P A t A t a Itv G b = a b | a P A b P A t A t a Itv G b
12 1 10 2 3 7 4 6 11 5 elplng φ X A E Y X A X hp 𝒢 G A Y X a b | a P A b P A t A t a Itv G b Y
13 9 12 mpbird φ X A E Y