Metamath Proof Explorer


Theorem ifnmfalse

Description: If A is not a member of B, but an "if" condition requires it, then the "false" branch results. This is a simple utility to provide a slight shortening and simplification of proofs versus applying iffalse directly in this case. (Contributed by David A. Wheeler, 15-May-2015)

Ref Expression
Assertion ifnmfalse A B if A B C D = D

Proof

Step Hyp Ref Expression
1 df-nel A B ¬ A B
2 iffalse ¬ A B if A B C D = D
3 1 2 sylbi A B if A B C D = D