Metamath Proof Explorer


Theorem in32

Description: A rearrangement of intersection. (Contributed by NM, 21-Apr-2001) (Proof shortened by Andrew Salmon, 26-Jun-2011)

Ref Expression
Assertion in32 A B C = A C B

Proof

Step Hyp Ref Expression
1 inass A B C = A B C
2 in12 A B C = B A C
3 incom B A C = A C B
4 1 2 3 3eqtri A B C = A C B