Metamath Proof Explorer


Theorem in4

Description: Rearrangement of intersection of 4 classes. (Contributed by NM, 21-Apr-2001)

Ref Expression
Assertion in4 ⊢ A ∩ B ∩ C ∩ D = A ∩ C ∩ B ∩ D

Proof

Step Hyp Ref Expression
1 in12 ⊢ B ∩ C ∩ D = C ∩ B ∩ D
2 1 ineq2i ⊢ A ∩ B ∩ C ∩ D = A ∩ C ∩ B ∩ D
3 inass ⊢ A ∩ B ∩ C ∩ D = A ∩ B ∩ C ∩ D
4 inass ⊢ A ∩ C ∩ B ∩ D = A ∩ C ∩ B ∩ D
5 2 3 4 3eqtr4i ⊢ A ∩ B ∩ C ∩ D = A ∩ C ∩ B ∩ D