Metamath Proof Explorer


Theorem indifcom

Description: Commutation law for intersection and difference. (Contributed by Scott Fenton, 18-Feb-2013)

Ref Expression
Assertion indifcom ABC=BAC

Proof

Step Hyp Ref Expression
1 incom AB=BA
2 1 difeq1i ABC=BAC
3 indif2 ABC=ABC
4 indif2 BAC=BAC
5 2 3 4 3eqtr4i ABC=BAC