Metamath Proof Explorer


Theorem indif2

Description: Bring an intersection in and out of a class difference. (Contributed by Jeff Hankins, 15-Jul-2009)

Ref Expression
Assertion indif2 ⊢ A ∩ B ∖ C = A ∩ B ∖ C

Proof

Step Hyp Ref Expression
1 inass ⊢ A ∩ B ∩ V ∖ C = A ∩ B ∩ V ∖ C
2 invdif ⊢ A ∩ B ∩ V ∖ C = A ∩ B ∖ C
3 invdif ⊢ B ∩ V ∖ C = B ∖ C
4 3 ineq2i ⊢ A ∩ B ∩ V ∖ C = A ∩ B ∖ C
5 1 2 4 3eqtr3ri ⊢ A ∩ B ∖ C = A ∩ B ∖ C