Metamath Proof Explorer


Theorem indif1

Description: Bring an intersection in and out of a class difference. (Contributed by Mario Carneiro, 15-May-2015)

Ref Expression
Assertion indif1 ACB=ABC

Proof

Step Hyp Ref Expression
1 indif2 BAC=BAC
2 incom BAC=ACB
3 incom BA=AB
4 3 difeq1i BAC=ABC
5 1 2 4 3eqtr3i ACB=ABC