Metamath Proof Explorer


Theorem invdif

Description: Intersection with universal complement. Remark in Stoll p. 20. (Contributed by NM, 17-Aug-2004)

Ref Expression
Assertion invdif ⊢ A ∩ V ∖ B = A ∖ B

Proof

Step Hyp Ref Expression
1 dfin2 ⊢ A ∩ V ∖ B = A ∖ V ∖ V ∖ B
2 ddif ⊢ V ∖ V ∖ B = B
3 2 difeq2i ⊢ A ∖ V ∖ V ∖ B = A ∖ B
4 1 3 eqtri ⊢ A ∩ V ∖ B = A ∖ B