Metamath Proof Explorer


Theorem intex

Description: The intersection of a nonempty class exists. Exercise 5 of TakeutiZaring p. 44 and its converse. (Contributed by NM, 13-Aug-2002)

Ref Expression
Assertion intex ⊢ A ≠ ∅ ↔ ⋂ A ∈ V

Proof

Step Hyp Ref Expression
1 n0 ⊢ A ≠ ∅ ↔ ∃ x x ∈ A
2 intss1 ⊢ x ∈ A → ⋂ A ⊆ x
3 vex ⊢ x ∈ V
4 3 ssex ⊢ ⋂ A ⊆ x → ⋂ A ∈ V
5 2 4 syl ⊢ x ∈ A → ⋂ A ∈ V
6 5 exlimiv ⊢ ∃ x x ∈ A → ⋂ A ∈ V
7 1 6 sylbi ⊢ A ≠ ∅ → ⋂ A ∈ V
8 vprc ⊢ ¬ V ∈ V
9 inteq ⊢ A = ∅ → ⋂ A = ⋂ ∅
10 int0 ⊢ ⋂ ∅ = V
11 9 10 eqtrdi ⊢ A = ∅ → ⋂ A = V
12 11 eleq1d ⊢ A = ∅ → ⋂ A ∈ V ↔ V ∈ V
13 8 12 mtbiri ⊢ A = ∅ → ¬ ⋂ A ∈ V
14 13 necon2ai ⊢ ⋂ A ∈ V → A ≠ ∅
15 7 14 impbii ⊢ A ≠ ∅ ↔ ⋂ A ∈ V