Metamath Proof Explorer


Theorem lmimfn

Description: Lemma for module isomorphisms. (Contributed by Stefan O'Rear, 23-Aug-2015)

Ref Expression
Assertion lmimfn ⊢ LMIso Fn LMod × LMod

Proof

Step Hyp Ref Expression
1 df-lmim ⊢ LMIso = s ∈ LMod , t ∈ LMod ⟼ g ∈ s LMHom t | g : Base s ⟶ 1-1 onto Base t
2 ovex ⊢ s LMHom t ∈ V
3 2 rabex ⊢ g ∈ s LMHom t | g : Base s ⟶ 1-1 onto Base t ∈ V
4 1 3 fnmpoi ⊢ LMIso Fn LMod × LMod