Metamath Proof Explorer


Theorem ltsubs2d

Description: Subtraction from both sides of surreal less-than. (Contributed by Scott Fenton, 5-Feb-2025)

Ref Expression
Hypotheses ltsubsd.1 ⊢ φ → A ∈ No
ltsubsd.2 ⊢ φ → B ∈ No
ltsubsd.3 ⊢ φ → C ∈ No
Assertion ltsubs2d ⊢ φ → A < s B ↔ C - s B < s C - s A

Proof

Step Hyp Ref Expression
1 ltsubsd.1 ⊢ φ → A ∈ No
2 ltsubsd.2 ⊢ φ → B ∈ No
3 ltsubsd.3 ⊢ φ → C ∈ No
4 ltsubs2 ⊢ A ∈ No ∧ B ∈ No ∧ C ∈ No → A < s B ↔ C - s B < s C - s A
5 1 2 3 4 syl3anc ⊢ φ → A < s B ↔ C - s B < s C - s A