Metamath Proof Explorer


Theorem mdandyvrx14

Description: Given the exclusivities set in the hypotheses, there exist a proof where ch, th, ta, et exclude ze, si accordingly. (Contributed by Jarvin Udandy, 7-Sep-2016)

Ref Expression
Hypotheses mdandyvrx14.1 ⊢ φ ⊻ ζ
mdandyvrx14.2 ⊢ ψ ⊻ σ
mdandyvrx14.3 ⊢ χ ↔ φ
mdandyvrx14.4 ⊢ θ ↔ ψ
mdandyvrx14.5 ⊢ τ ↔ ψ
mdandyvrx14.6 ⊢ η ↔ ψ
Assertion mdandyvrx14 ⊢ χ ⊻ ζ ∧ θ ⊻ σ ∧ τ ⊻ σ ∧ η ⊻ σ

Proof

Step Hyp Ref Expression
1 mdandyvrx14.1 ⊢ φ ⊻ ζ
2 mdandyvrx14.2 ⊢ ψ ⊻ σ
3 mdandyvrx14.3 ⊢ χ ↔ φ
4 mdandyvrx14.4 ⊢ θ ↔ ψ
5 mdandyvrx14.5 ⊢ τ ↔ ψ
6 mdandyvrx14.6 ⊢ η ↔ ψ
7 2 1 3 4 5 6 mdandyvrx1 ⊢ χ ⊻ ζ ∧ θ ⊻ σ ∧ τ ⊻ σ ∧ η ⊻ σ