Metamath Proof Explorer


Theorem mdandyvrx15

Description: Given the exclusivities set in the hypotheses, there exist a proof where ch, th, ta, et exclude ze, si accordingly. (Contributed by Jarvin Udandy, 7-Sep-2016)

Ref Expression
Hypotheses mdandyvrx15.1 ⊢ φ ⊻ ζ
mdandyvrx15.2 ⊢ ψ ⊻ σ
mdandyvrx15.3 ⊢ χ ↔ ψ
mdandyvrx15.4 ⊢ θ ↔ ψ
mdandyvrx15.5 ⊢ τ ↔ ψ
mdandyvrx15.6 ⊢ η ↔ ψ
Assertion mdandyvrx15 ⊢ χ ⊻ σ ∧ θ ⊻ σ ∧ τ ⊻ σ ∧ η ⊻ σ

Proof

Step Hyp Ref Expression
1 mdandyvrx15.1 ⊢ φ ⊻ ζ
2 mdandyvrx15.2 ⊢ ψ ⊻ σ
3 mdandyvrx15.3 ⊢ χ ↔ ψ
4 mdandyvrx15.4 ⊢ θ ↔ ψ
5 mdandyvrx15.5 ⊢ τ ↔ ψ
6 mdandyvrx15.6 ⊢ η ↔ ψ
7 2 1 3 4 5 6 mdandyvrx0 ⊢ χ ⊻ σ ∧ θ ⊻ σ ∧ τ ⊻ σ ∧ η ⊻ σ