Metamath Proof Explorer


Theorem mdandyvrx15

Description: Given the exclusivities set in the hypotheses, there exist a proof where ch, th, ta, et exclude ze, si accordingly. (Contributed by Jarvin Udandy, 7-Sep-2016)

Ref Expression
Hypotheses mdandyvrx15.1 ⊢ ( 𝜑 ⊻ 𝜁 )
mdandyvrx15.2 ⊢ ( 𝜓 ⊻ 𝜎 )
mdandyvrx15.3 ⊢ ( 𝜒 ↔ 𝜓 )
mdandyvrx15.4 ⊢ ( 𝜃 ↔ 𝜓 )
mdandyvrx15.5 ⊢ ( 𝜏 ↔ 𝜓 )
mdandyvrx15.6 ⊢ ( 𝜂 ↔ 𝜓 )
Assertion mdandyvrx15 ( ( ( ( 𝜒 ⊻ 𝜎 ) ∧ ( 𝜃 ⊻ 𝜎 ) ) ∧ ( 𝜏 ⊻ 𝜎 ) ) ∧ ( 𝜂 ⊻ 𝜎 ) )

Proof

Step Hyp Ref Expression
1 mdandyvrx15.1 ⊢ ( 𝜑 ⊻ 𝜁 )
2 mdandyvrx15.2 ⊢ ( 𝜓 ⊻ 𝜎 )
3 mdandyvrx15.3 ⊢ ( 𝜒 ↔ 𝜓 )
4 mdandyvrx15.4 ⊢ ( 𝜃 ↔ 𝜓 )
5 mdandyvrx15.5 ⊢ ( 𝜏 ↔ 𝜓 )
6 mdandyvrx15.6 ⊢ ( 𝜂 ↔ 𝜓 )
7 2 1 3 4 5 6 mdandyvrx0 ⊢ ( ( ( ( 𝜒 ⊻ 𝜎 ) ∧ ( 𝜃 ⊻ 𝜎 ) ) ∧ ( 𝜏 ⊻ 𝜎 ) ) ∧ ( 𝜂 ⊻ 𝜎 ) )