Metamath Proof Explorer


Theorem mdandyvrx15

Description: Given the exclusivities set in the hypotheses, there exist a proof where ch, th, ta, et exclude ze, si accordingly. (Contributed by Jarvin Udandy, 7-Sep-2016)

Ref Expression
Hypotheses mdandyvrx15.1 ( 𝜑𝜁 )
mdandyvrx15.2 ( 𝜓𝜎 )
mdandyvrx15.3 ( 𝜒𝜓 )
mdandyvrx15.4 ( 𝜃𝜓 )
mdandyvrx15.5 ( 𝜏𝜓 )
mdandyvrx15.6 ( 𝜂𝜓 )
Assertion mdandyvrx15 ( ( ( ( 𝜒𝜎 ) ∧ ( 𝜃𝜎 ) ) ∧ ( 𝜏𝜎 ) ) ∧ ( 𝜂𝜎 ) )

Proof

Step Hyp Ref Expression
1 mdandyvrx15.1 ( 𝜑𝜁 )
2 mdandyvrx15.2 ( 𝜓𝜎 )
3 mdandyvrx15.3 ( 𝜒𝜓 )
4 mdandyvrx15.4 ( 𝜃𝜓 )
5 mdandyvrx15.5 ( 𝜏𝜓 )
6 mdandyvrx15.6 ( 𝜂𝜓 )
7 2 1 3 4 5 6 mdandyvrx0 ( ( ( ( 𝜒𝜎 ) ∧ ( 𝜃𝜎 ) ) ∧ ( 𝜏𝜎 ) ) ∧ ( 𝜂𝜎 ) )