Theorem mdandyvrx15

Description: Given the exclusivities set in the hypotheses, there exist a proof where ch, th, ta, et exclude ze, si accordingly. (Contributed by Jarvin Udandy, 7-Sep-2016)

	Ref	Expression
Hypotheses	mdandyvrx15.1	|- ( ph \/_ ze )
	mdandyvrx15.2	|- ( ps \/_ si )
	mdandyvrx15.3	|- ( ch <-> ps )
	mdandyvrx15.4	|- ( th <-> ps )
	mdandyvrx15.5	|- ( ta <-> ps )
	mdandyvrx15.6	|- ( et <-> ps )
Assertion	mdandyvrx15	|- ( ( ( ( ch \/_ si ) /\ ( th \/_ si ) ) /\ ( ta \/_ si ) ) /\ ( et \/_ si ) )

Proof

Step	Hyp	Ref	Expression
1		mdandyvrx15.1	|- ( ph \/_ ze )
2		mdandyvrx15.2	|- ( ps \/_ si )
3		mdandyvrx15.3	|- ( ch <-> ps )
4		mdandyvrx15.4	|- ( th <-> ps )
5		mdandyvrx15.5	|- ( ta <-> ps )
6		mdandyvrx15.6	|- ( et <-> ps )
7	2 1 3 4 5 6	mdandyvrx0	|- ( ( ( ( ch \/_ si ) /\ ( th \/_ si ) ) /\ ( ta \/_ si ) ) /\ ( et \/_ si ) )