Metamath Proof Explorer


Theorem mdsym

Description: M-symmetry of the Hilbert lattice. Lemma 5 of Maeda p. 168. (Contributed by NM, 6-Jul-2004) (New usage is discouraged.)

Ref Expression
Assertion mdsym ⊢ A ∈ C ℋ ∧ B ∈ C ℋ → A 𝑀 ℋ B ↔ B 𝑀 ℋ A

Proof

Step Hyp Ref Expression
1 breq1 ⊢ A = if A ∈ C ℋ A ℋ → A 𝑀 ℋ B ↔ if A ∈ C ℋ A ℋ 𝑀 ℋ B
2 breq2 ⊢ A = if A ∈ C ℋ A ℋ → B 𝑀 ℋ A ↔ B 𝑀 ℋ if A ∈ C ℋ A ℋ
3 1 2 bibi12d ⊢ A = if A ∈ C ℋ A ℋ → A 𝑀 ℋ B ↔ B 𝑀 ℋ A ↔ if A ∈ C ℋ A ℋ 𝑀 ℋ B ↔ B 𝑀 ℋ if A ∈ C ℋ A ℋ
4 breq2 ⊢ B = if B ∈ C ℋ B ℋ → if A ∈ C ℋ A ℋ 𝑀 ℋ B ↔ if A ∈ C ℋ A ℋ 𝑀 ℋ if B ∈ C ℋ B ℋ
5 breq1 ⊢ B = if B ∈ C ℋ B ℋ → B 𝑀 ℋ if A ∈ C ℋ A ℋ ↔ if B ∈ C ℋ B ℋ 𝑀 ℋ if A ∈ C ℋ A ℋ
6 4 5 bibi12d ⊢ B = if B ∈ C ℋ B ℋ → if A ∈ C ℋ A ℋ 𝑀 ℋ B ↔ B 𝑀 ℋ if A ∈ C ℋ A ℋ ↔ if A ∈ C ℋ A ℋ 𝑀 ℋ if B ∈ C ℋ B ℋ ↔ if B ∈ C ℋ B ℋ 𝑀 ℋ if A ∈ C ℋ A ℋ
7 ifchhv ⊢ if A ∈ C ℋ A ℋ ∈ C ℋ
8 ifchhv ⊢ if B ∈ C ℋ B ℋ ∈ C ℋ
9 7 8 mdsymi ⊢ if A ∈ C ℋ A ℋ 𝑀 ℋ if B ∈ C ℋ B ℋ ↔ if B ∈ C ℋ B ℋ 𝑀 ℋ if A ∈ C ℋ A ℋ
10 3 6 9 dedth2h ⊢ A ∈ C ℋ ∧ B ∈ C ℋ → A 𝑀 ℋ B ↔ B 𝑀 ℋ A