Metamath Proof Explorer


Theorem mofsssn

Description: There is at most one function into a subclass of a singleton. (Contributed by Zhi Wang, 24-Sep-2024)

Ref Expression
Assertion mofsssn ⊢ B ⊆ Y → ∃* f f : A ⟶ B

Proof

Step Hyp Ref Expression
1 sssn ⊢ B ⊆ Y ↔ B = ∅ ∨ B = Y
2 mof02 ⊢ B = ∅ → ∃* f f : A ⟶ B
3 mofsn2 ⊢ B = Y → ∃* f f : A ⟶ B
4 2 3 jaoi ⊢ B = ∅ ∨ B = Y → ∃* f f : A ⟶ B
5 1 4 sylbi ⊢ B ⊆ Y → ∃* f f : A ⟶ B