Metamath Proof Explorer


Theorem nanan

Description: Conjunction in terms of alternative denial. (Contributed by Mario Carneiro, 9-May-2015)

Ref Expression
Assertion nanan ⊢ φ ∧ ψ ↔ ¬ φ ⊼ ψ

Proof

Step Hyp Ref Expression
1 df-nan ⊢ φ ⊼ ψ ↔ ¬ φ ∧ ψ
2 1 con2bii ⊢ φ ∧ ψ ↔ ¬ φ ⊼ ψ