Metamath Proof Explorer


Theorem nancom

Description: Alternative denial is commutative. Remark: alternative denial is not associative, see nanass . (Contributed by Mario Carneiro, 9-May-2015) (Proof shortened by Wolf Lammen, 26-Jun-2020)

Ref Expression
Assertion nancom ⊢ φ ⊼ ψ ↔ ψ ⊼ φ

Proof

Step Hyp Ref Expression
1 con2b ⊢ φ → ¬ ψ ↔ ψ → ¬ φ
2 dfnan2 ⊢ φ ⊼ ψ ↔ φ → ¬ ψ
3 dfnan2 ⊢ ψ ⊼ φ ↔ ψ → ¬ φ
4 1 2 3 3bitr4i ⊢ φ ⊼ ψ ↔ ψ ⊼ φ