Metamath Proof Explorer


Theorem necomd

Description: Deduction from commutative law for inequality. (Contributed by NM, 12-Feb-2008)

Ref Expression
Hypothesis necomd.1 ⊢ φ → A ≠ B
Assertion necomd ⊢ φ → B ≠ A

Proof

Step Hyp Ref Expression
1 necomd.1 ⊢ φ → A ≠ B
2 necom ⊢ A ≠ B ↔ B ≠ A
3 1 2 sylib ⊢ φ → B ≠ A