Metamath Proof Explorer


Theorem necon3abii

Description: Deduction from equality to inequality. (Contributed by NM, 9-Nov-2007)

Ref Expression
Hypothesis necon3abii.1 A=Bφ
Assertion necon3abii AB¬φ

Proof

Step Hyp Ref Expression
1 necon3abii.1 A=Bφ
2 df-ne AB¬A=B
3 2 1 xchbinx AB¬φ