Metamath Proof Explorer


Theorem necon3abii

Description: Deduction from equality to inequality. (Contributed by NM, 9-Nov-2007)

Ref Expression
Hypothesis necon3abii.1 ⊢ A = B ↔ φ
Assertion necon3abii ⊢ A ≠ B ↔ ¬ φ

Proof

Step Hyp Ref Expression
1 necon3abii.1 ⊢ A = B ↔ φ
2 df-ne ⊢ A ≠ B ↔ ¬ A = B
3 2 1 xchbinx ⊢ A ≠ B ↔ ¬ φ