Metamath Proof Explorer


Theorem necon3abii

Description: Deduction from equality to inequality. (Contributed by NM, 9-Nov-2007)

Ref Expression
Hypothesis necon3abii.1 ⊢ ( 𝐴 = 𝐵 ↔ 𝜑 )
Assertion necon3abii ( 𝐴 ≠ 𝐵 ↔ ¬ 𝜑 )

Proof

Step Hyp Ref Expression
1 necon3abii.1 ⊢ ( 𝐴 = 𝐵 ↔ 𝜑 )
2 df-ne ⊢ ( 𝐴 ≠ 𝐵 ↔ ¬ 𝐴 = 𝐵 )
3 2 1 xchbinx ⊢ ( 𝐴 ≠ 𝐵 ↔ ¬ 𝜑 )