Metamath Proof Explorer


Theorem necon3bbii

Description: Deduction from equality to inequality. (Contributed by NM, 13-Apr-2007)

Ref Expression
Hypothesis necon3bbii.1 ⊢ ( 𝜑 ↔ 𝐴 = 𝐵 )
Assertion necon3bbii ( ¬ 𝜑 ↔ 𝐴 ≠ 𝐵 )

Proof

Step Hyp Ref Expression
1 necon3bbii.1 ⊢ ( 𝜑 ↔ 𝐴 = 𝐵 )
2 1 bicomi ⊢ ( 𝐴 = 𝐵 ↔ 𝜑 )
3 2 necon3abii ⊢ ( 𝐴 ≠ 𝐵 ↔ ¬ 𝜑 )
4 3 bicomi ⊢ ( ¬ 𝜑 ↔ 𝐴 ≠ 𝐵 )