Metamath Proof Explorer


Theorem necon3bbii

Description: Deduction from equality to inequality. (Contributed by NM, 13-Apr-2007)

Ref Expression
Hypothesis necon3bbii.1 φA=B
Assertion necon3bbii ¬φAB

Proof

Step Hyp Ref Expression
1 necon3bbii.1 φA=B
2 1 bicomi A=Bφ
3 2 necon3abii AB¬φ
4 3 bicomi ¬φAB