Metamath Proof Explorer


Theorem bicomi

Description: Inference from commutative law for logical equivalence. (Contributed by NM, 3-Jan-1993)

Ref Expression
Hypothesis bicomi.1 ⊢ ( 𝜑 ↔ 𝜓 )
Assertion bicomi ( 𝜓 ↔ 𝜑 )

Proof

Step Hyp Ref Expression
1 bicomi.1 ⊢ ( 𝜑 ↔ 𝜓 )
2 bicom1 ⊢ ( ( 𝜑 ↔ 𝜓 ) → ( 𝜓 ↔ 𝜑 ) )
3 1 2 ax-mp ⊢ ( 𝜓 ↔ 𝜑 )