Metamath Proof Explorer


Theorem necon3bbii

Description: Deduction from equality to inequality. (Contributed by NM, 13-Apr-2007)

Ref Expression
Hypothesis necon3bbii.1 ⊢ φ ↔ A = B
Assertion necon3bbii ⊢ ¬ φ ↔ A ≠ B

Proof

Step Hyp Ref Expression
1 necon3bbii.1 ⊢ φ ↔ A = B
2 1 bicomi ⊢ A = B ↔ φ
3 2 necon3abii ⊢ A ≠ B ↔ ¬ φ
4 3 bicomi ⊢ ¬ φ ↔ A ≠ B