Metamath Proof Explorer


Theorem neg1s

Description: An expression for negative surreal one. (Contributed by Scott Fenton, 24-Jul-2025)

Ref Expression
Assertion neg1s ⊢ + s ⁡ 1 s = ∅ | s 0 s

Proof

Step Hyp Ref Expression
1 1no ⊢ 1 s ∈ No
2 negsval ⊢ 1 s ∈ No → + s ⁡ 1 s = + s R ⁡ 1 s | s + s L ⁡ 1 s
3 1 2 ax-mp ⊢ + s ⁡ 1 s = + s R ⁡ 1 s | s + s L ⁡ 1 s
4 right1s ⊢ R ⁡ 1 s = ∅
5 4 imaeq2i ⊢ + s R ⁡ 1 s = + s ∅
6 ima0 ⊢ + s ∅ = ∅
7 5 6 eqtri ⊢ + s R ⁡ 1 s = ∅
8 left1s ⊢ L ⁡ 1 s = 0 s
9 8 imaeq2i ⊢ + s L ⁡ 1 s = + s 0 s
10 negsfn ⊢ + s Fn No
11 0no ⊢ 0 s ∈ No
12 fnimapr ⊢ + s Fn No ∧ 0 s ∈ No ∧ 0 s ∈ No → + s 0 s 0 s = + s ⁡ 0 s + s ⁡ 0 s
13 10 11 11 12 mp3an ⊢ + s 0 s 0 s = + s ⁡ 0 s + s ⁡ 0 s
14 neg0s ⊢ + s ⁡ 0 s = 0 s
15 14 14 preq12i ⊢ + s ⁡ 0 s + s ⁡ 0 s = 0 s 0 s
16 13 15 eqtri ⊢ + s 0 s 0 s = 0 s 0 s
17 dfsn2 ⊢ 0 s = 0 s 0 s
18 17 imaeq2i ⊢ + s 0 s = + s 0 s 0 s
19 16 18 17 3eqtr4i ⊢ + s 0 s = 0 s
20 9 19 eqtri ⊢ + s L ⁡ 1 s = 0 s
21 7 20 oveq12i ⊢ + s R ⁡ 1 s | s + s L ⁡ 1 s = ∅ | s 0 s
22 3 21 eqtri ⊢ + s ⁡ 1 s = ∅ | s 0 s