Metamath Proof Explorer


Theorem negcut2

Description: The cut that defines surreal negation is legitimate. (Contributed by Scott Fenton, 3-Feb-2025)

Ref Expression
Assertion negcut2 ⊢ A ∈ No → + s R ⁡ A ≪ s + s L ⁡ A

Proof

Step Hyp Ref Expression
1 negcut ⊢ A ∈ No → + s ⁡ A ∈ No ∧ + s R ⁡ A ≪ s + s ⁡ A ∧ + s ⁡ A ≪ s + s L ⁡ A
2 1 simp2d ⊢ A ∈ No → + s R ⁡ A ≪ s + s ⁡ A
3 1 simp3d ⊢ A ∈ No → + s ⁡ A ≪ s + s L ⁡ A
4 fvex ⊢ + s ⁡ A ∈ V
5 4 snnz ⊢ + s ⁡ A ≠ ∅
6 sltstr ⊢ + s R ⁡ A ≪ s + s ⁡ A ∧ + s ⁡ A ≪ s + s L ⁡ A ∧ + s ⁡ A ≠ ∅ → + s R ⁡ A ≪ s + s L ⁡ A
7 5 6 mp3an3 ⊢ + s R ⁡ A ≪ s + s ⁡ A ∧ + s ⁡ A ≪ s + s L ⁡ A → + s R ⁡ A ≪ s + s L ⁡ A
8 2 3 7 syl2anc ⊢ A ∈ No → + s R ⁡ A ≪ s + s L ⁡ A