Metamath Proof Explorer
		
		
		
		Description:  From the general negation of membership in A , infer that A is
       the empty set.  (Contributed by BJ, 6-Oct-2018)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypothesis | nel0.1 |  | 
				
					|  | Assertion | nel0 |  | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | nel0.1 |  | 
						
							| 2 |  | eq0 |  | 
						
							| 3 | 2 1 | mpgbir |  |