Metamath Proof Explorer


Theorem nel0

Description: From the general negation of membership in A , infer that A is the empty set. (Contributed by BJ, 6-Oct-2018)

Ref Expression
Hypothesis nel0.1 ⊢ ¬ x ∈ A
Assertion nel0 ⊢ A = ∅

Proof

Step Hyp Ref Expression
1 nel0.1 ⊢ ¬ x ∈ A
2 eq0 ⊢ A = ∅ ↔ ∀ x ¬ x ∈ A
3 2 1 mpgbir ⊢ A = ∅