Metamath Proof Explorer


Theorem nelss

Description: Demonstrate by witnesses that two classes lack a subclass relation. (Contributed by Stefan O'Rear, 5-Feb-2015)

Ref Expression
Assertion nelss ⊢ A ∈ B ∧ ¬ A ∈ C → ¬ B ⊆ C

Proof

Step Hyp Ref Expression
1 ssel ⊢ B ⊆ C → A ∈ B → A ∈ C
2 1 com12 ⊢ A ∈ B → B ⊆ C → A ∈ C
3 2 con3dimp ⊢ A ∈ B ∧ ¬ A ∈ C → ¬ B ⊆ C